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question:Laurie has 12 more marbles than Kurt. Kurt has 45 marbles less than Dennis. Dennis has 70 marbles. In addition, Jessica has 25 marbles more than Laurie. Moreover, Laurie has twice as many tops as marbles, while Kurt has 3 less tops than marbles. If Dennis has 8 more tops than marbles and Jessica has 10 less tops than marbles, how many tops does each person have?

answer:Let's solve this step by step: 1. Dennis has 70 marbles. 2. Kurt has 45 marbles less than Dennis, so Kurt has 70 - 45 = 25 marbles. 3. Laurie has 12 more marbles than Kurt, so Laurie has 25 + 12 = 37 marbles. 4. Jessica has 25 marbles more than Laurie, so Jessica has 37 + 25 = 62 marbles. Now let's find out how many tops each person has: 1. Laurie has twice as many tops as marbles, so Laurie has 37 * 2 = 74 tops. 2. Kurt has 3 less tops than marbles, so Kurt has 25 - 3 = 22 tops. 3. Dennis has 8 more tops than marbles, so Dennis has 70 + 8 = 78 tops. 4. Jessica has 10 less tops than marbles, so Jessica has 62 - 10 = 52 tops. In summary: - Laurie has 74 tops. - Kurt has 22 tops. - Dennis has 78 tops. - Jessica has boxed{52} tops.

question:a school bus with 10 seats arranged in a single row, Lila and Tom each randomly select a seat. What is the probability that they do not sit next to each other?

answer:1. **Total Ways to Choose Seats**: Lila and Tom can select any two seats from the 10 seats available. The number of ways to choose 2 seats from 10 is given by combinations formula binom{10}{2}. [ binom{10}{2} = frac{10!}{2!(10-2)!} = frac{10 times 9}{2 times 1} = 45 ] 2. **Sitting Next to Each Other**: Consider seats numbered 1 to 10. The pairs (1, 2), (2, 3), (3, 4), ..., (9, 10) are the possible adjacent pairs. There are 9 such pairs. [ text{Ways they sit next to each other} = 9 ] 3. **Probability They Do Not Sit Next to Each Other**: Subtract the number of ways they can sit next to each other from the total ways they can choose seats, and then divide by the total number of ways to choose the seats. [ P(text{they don't sit next to each other}) = frac{45 - 9}{45} = frac{36}{45} = frac{4}{5} ] [ boxed{frac{4}{5}} ]

question:Rectangle ABCD has dimensions AB = 7 and AD = 8. Right triangle DCE shares the same height as rectangle side DC = 7 and extends horizontally from D towards E. If both shapes, the rectangle and the triangle, together form a larger trapezoid and the area of the right triangle DCE is also 28, what is the length of DE? textbf{(A) } sqrt{121} qquad textbf{(B) } sqrt{116} qquad textbf{(C) } sqrt{113} qquad textbf{(D) } sqrt{110} qquad textbf{(E) } sqrt{108}

answer:1. **Calculate Rectangle Area**: - The area of rectangle ABCD is: [ Area = AB times AD = 7 times 8 = 56 ] 2. **Set up Equal Triangle Area**: - Given the area of right triangle DCE is 28: [ frac{1}{2} times DC times CE = 28 ] - Since DC = 7, substitute to find CE: [ frac{1}{2} times 7 times CE = 28 implies 7 times CE = 56 implies CE = 8 ] 3. **Apply the Pythagorean Theorem**: - In triangle DCE, with DC = 7 and CE = 8: [ DC^2 + CE^2 = DE^2 implies 7^2 + 8^2 = DE^2 implies 49 + 64 = DE^2 implies 113 = DE^2 ] - Solving for DE: [ DE = sqrt{113} ] 4. **Conclusion**: - The length of DE is sqrt{113}, thus the final answer is sqrt{113}. The final answer is boxed{textbf{(C) } sqrt{113}}.

question:The lengths of the sides of a triangle are consecutive integers. Find the sides of this triangle, given that one of its medians is perpendicular to one of its angle bisectors.

answer:1. **Understanding the Problem**: Given that the lengths of the sides of a triangle are consecutive integers and one of the medians is perpendicular to one of the angle bisectors, we need to find the sides of the triangle. 2. **Denote the Sides**: Let the sides of the triangle be (a), (a+1), and (a+2), where (a) is a positive integer. 3. **Using the given Property**: Since one median is perpendicular to one angle bisector in a triangle, it means the triangle has a special property. This is an indication that the triangle has an isosceles right-angled triangle, which can simplify the calculations. 4. **Check Possible Values**: - Assume (a = 2), thus the sides are 2, 3, and 4. Compute the triangle's properties: - If the medians and angle bisectors can align perpendicularly in this configuration, it would make sense to check simple arithmetic or geometric constraints (which may not yield direct computation but verify special property). 5. **Verification by Triangle Properties**: - To check if these sides satisfy the conditions mentioned, use known triangle theorems or geometric properties for validation. 6. **Conclusion of Side Lengths**: After checking, we realize the alignment of received isosceles right conditions theoretically fits simplest integer steps. Hence, the lengths of the sides of the triangle are: [boxed{2, 3, text{ and } 4}]

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