answer:For an integer to be divisible by 3, the sum of its digits must be divisible by 3. The sum of the digits of 63underline{hphantom{0}} is 6+3=9, which is divisible by 3. To find the largest possible difference between two potential units digits, we want to maximize the units digit and minimize the tens digit. The largest possible units digit is 9, and the smallest possible tens digit is 0. Therefore, the largest possible difference between two potential units digits is 9-0=boxed{9}. The answer is: 9

answer:The company currently produces 100 cars per month. To reach a target of 1800 cars per year, the company needs to produce 1800/12 = 150 cars per month. So, the company needs to add 150 - 100 = 50 cars to the monthly production rate to reach the target. 50 The answer is: 50

answer:We can start by simplifying the congruence. Subtracting 531n from both sides gives 0 equiv 536n pmod{24}. Since 536 = 24 cdot 22 + 8, we can simplify further to 0 equiv 8n pmod{24}. This means that 8n is divisible by 24. The smallest positive integer n that satisfies this is n = boxed{3}. The answer is: 3

answer:If 5 squirrels collected a total of 575 acorns, then on average each squirrel collected 575/5 = 115 acorns. Each squirrel needs 130 acorns to get through the winter, so they need to collect 130 - 115 = 15 more acorns. Therefore, each squirrel needs to collect 15 more acorns. 15 The answer is: 15