answer:Let x_1, x_2, x_3, dots be the terms of the sequence. We are given that the mean of the first n terms is n, so we have the equation [frac{x_1 + x_2 + x_3 + dots + x_n}{n} = n.] Multiplying both sides by n gives us [x_1 + x_2 + x_3 + dots + x_n = n^2.] Since the mean of the first n terms is n, we know that the sum of the first n terms is n^2. The 2008th term is the sum of all the terms up to and including the 2008th term, minus the sum of all the terms up to and including the 2007th term. The sum of the first 2008 terms is 2008^2, and the sum of the first 2007 terms is 2007^2. Therefore, the 2008th term is 2008^2 - 2007^2 = (2008 + 2007)(2008 - 2007) = boxed{4015}. The answer is: 4015

answer:Since the coefficient of x^2 is positive, the parabola represented by the equation y=3x^2+6x+9 opens upwards. This means that the vertex of the parabola represents the minimum value of y. The x-coordinate of the vertex can be found using the formula x=-frac{b}{2a}, where a is the coefficient of x^2 and b is the coefficient of x. In this case, a=3 and b=6, so x=-frac{6}{2(3)}=-1. To find the y-coordinate of the vertex, we substitute x=-1 into the equation: y=3(-1)^2+6(-1)+9=3-6+9=6. Thus, the minimum value of y is boxed{6}. The answer is: 6

answer:We can rewrite the equation as 2a + 3b = 8. In order for 2b + 12 to be divisible by a positive integer, we need 2b + 12 to be divisible by both 2 and 3. Since 2a is always even, we know that 2a + 3b will be even if and only if 3b is even. Therefore, b must be even. Out of the first six positive integers (1, 2, 3, 4, 5, 6), three of them (2, 4, 6) are even. Thus, three of the first six positive integers must be divisors of 2b + 12. The answer is: 3

answer:If the pickup carries ten bags per trip and makes 20 trips, then it carries a total of 10 * 20 = 200 bags. Since each bag weighs 50 kgs, the total weight of the onions harvested is 200 * 50 = 10,000 kgs. 10000 The answer is: 10000