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question:Nico borrows 3 books from the library on Monday. On Monday, he reads the first book with a total of x pages. On Tuesday, he reads the second book with a total of 12 pages. On Wednesday, he reads the third book. If he has read a total of 51 pages from Monday to Wednesday, how many pages did he read on Wednesday? If we know the answer to the above question is 19, what is the value of unknown variable x?

answer:On Monday, Nico reads the first book with x pages. On Tuesday, he reads the second book with 12 pages. On Wednesday, he reads the third book. Let's represent the number of pages he reads on Wednesday as y. The total number of pages Nico reads from Monday to Wednesday is the sum of the number of pages he reads each day: x + 12 + y. We are given that the total number of pages Nico reads from Monday to Wednesday is 51, so we can write: x + 12 + y = 51. Simplifying, we get: x + y = 39. We are also given that the number of pages Nico read on Wednesday is 19, so we can write: y = 19. Solving for x, we get: x = 39 - y = 39 - 19 = 20. The value of x is 20. 20 The answer is: 20

question:f the cost of a child's ticket is half the cost of an adult's ticket, and the total cost for six kids and two adults is 50, what is the price of one child's ticket?

answer:Let's assume the cost of an adult's ticket is X dollars. Then, the cost of a child's ticket would be X/2 dollars. The total cost for six kids would be 6 * (X/2) = 3X dollars. The total cost for two adults would be 2 * X = 2X dollars. Given that the total cost for six kids and two adults is 50, we have the equation: 3X + 2X = 50 Combining like terms, we get: 5X = 50 Dividing both sides by 5, we get: X = 10 So, the cost of an adult's ticket is 10. Therefore, the cost of a child's ticket is 10/2 = 5. 5 The answer is: 5

question:The same amount of steel used to create eight solid steel balls, each with a radius of 1 inch, is used to create one larger steel ball. What is the radius of the larger ball? [asy] size(150); filldraw(circle((0,0),1),gray); filldraw(circle((.9,-.8),1),gray); filldraw(circle((1.8,.9),1),gray); filldraw(circle((2,0),1),gray); filldraw(circle((2,-.4),1),gray); filldraw(circle((3,-.4),1),gray); filldraw(circle((4.8,-.4),1),gray); filldraw(circle((3.2,.5),1),gray); draw((6,.7)--(8,.7),Arrow); filldraw(circle((11,.2),2),gray); [/asy]

answer:The volume of a ball with radius r is frac{4}{3}pi r^3. So, the volume of one of the smaller balls is frac{4}{3}pi(1^3)=frac{4}{3}pi cubic inches. The total volume of the eight smaller balls is 8cdotfrac{4}{3}pi=frac{32}{3}pi cubic inches. The volume of the larger ball is also frac{32}{3}pi cubic inches. Let the radius of the larger ball be R. Then, the volume of the larger ball is frac{4}{3}pi R^3 cubic inches. Setting this equal to frac{32}{3}pi, we have frac{4}{3}pi R^3=frac{32}{3}pi. Dividing both sides by frac{4}{3}pi, we have R^3=8. Taking the cube root of both sides, we have R=2. So, the radius of the larger ball is boxed{2} inches. The answer is: 2

question:Audrey was asleep for 10 hours last night and dreamed for 2/5 of the time. How much of the night was she not dreaming?

answer:If Audrey was asleep for 10 hours, and she dreamed for 2/5 of that time, she dreamed for 10 * 2/5 = 4 hours. To find out how much of the night she was not dreaming, we subtract the time she was dreaming from the total time she was asleep. So, she was not dreaming for 10 - 4 = 6 hours. 6 The answer is: 6