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question:Given that the curve f(x)=aln x+x^2 has a tangent line parallel to the line x+y=0 at the point (1,1), the value of the real number a is ( ). A: 3 B: 1 C: 2 D: 3

answer:To find the value of a, we start by differentiating the given function f(x) = aln x + x^2 with respect to x. This gives us the derivative of the function, which represents the slope of the tangent line at any point on the curve. The derivative is calculated as follows: [ f'(x) = frac{d}{dx}(aln x + x^2) = frac{a}{x} + 2x ] Given that the tangent line at the point (1,1) is parallel to the line x+y=0, we know that the slope of this line is -1 (since the slope of x+y=0 can be rewritten as y=-x, which has a slope of -1). The slope of the tangent line to the curve at any point (x, f(x)) is given by f'(x). Therefore, at the point (1,1), we have: [ f'(1) = frac{a}{1} + 2(1) = a + 2 ] Since this slope must equal -1 (to be parallel to x+y=0), we set f'(1) = -1 and solve for a: [ a + 2 = -1 implies a = -1 - 2 implies a = -3 ] Thus, the value of the real number a that satisfies the given conditions is -3. Therefore, the correct answer is boxed{text{A}}.

question:A train of a certain length takes 6 sec to cross a man walking at 5 kmph in a direction opposite to that of the train. The speed of the train is 69.994 kmph. What is the length of the train?

answer:To find the length of the train, we need to calculate the relative speed between the train and the man and then use the time it takes for the train to cross the man to find the length. The speed of the train is 69.994 kmph, and the man is walking at 5 kmph in the opposite direction. When two objects are moving in opposite directions, their relative speed is the sum of their individual speeds. Relative speed = Speed of train + Speed of man Relative speed = 69.994 kmph + 5 kmph Relative speed = 74.994 kmph Now, we need to convert this speed into meters per second to be consistent with the time given in seconds. 1 kmph = 1000 meters / 3600 seconds 74.994 kmph = 74.994 * 1000 / 3600 m/s Let's calculate that: 74.994 * 1000 / 3600 = 20.8311 m/s (approximately) Now we have the relative speed in meters per second. The train takes 6 seconds to cross the man, so we can find the length of the train (L) by multiplying the relative speed by the time taken. L = Relative speed * Time L = 20.8311 m/s * 6 s L = 124.9866 meters Therefore, the length of the train is approximately boxed{124.9866} meters.

question:A frog makes 4 jumps, each exactly 1 meter long. The directions of the jumps are chosen independently at random. What is the probability that the frog's final position is no more than 1.5 meters from its starting position? textbf{(A)} dfrac{1}{10} qquad textbf{(B)} dfrac{1}{7} qquad textbf{(C)} dfrac{1}{5} qquad textbf{(D)} dfrac{1}{3} qquad textbf{(E)} dfrac{1}{2}

answer:Step 1: Understanding the Problem The frog now makes 4 jumps of 1 meter each in random directions. We need to find the probability that the distance from the starting point to the final position is at most 1.5 meters. Step 2: Using Vector Representation for Jumps Let the jumps be denoted as vectors vec{u}, vec{v}, vec{w}, vec{x}, each having magnitude 1. The final position of the frog relative to the starting point is vec{r} = vec{u} + vec{v} + vec{w} + vec{x}. Step 3: Calculating the Probability The probability that the magnitude of vec{r} is at most 1.5 involves considering the distribution of vector sum vec{r}. The distribution of vec{r}, being the sum of four independent unit vectors in random directions, is more centrally concentrated compared to three vectors due to the Central Limit Theorem. Step 4: Estimating the Probability Using geometric intuition and analytical or simulation methods, we estimate this probability. The probability density function for the length of the sum of four unit vectors in random directions is complex but can be estimated or simulated. For four jumps, the increased number of vectors generally pulls the resultant vector's magnitude closer to the center more often compared to three jumps. Conclusion Simulation and analytical techniques suggest that the probability that the sum of four unit vectors results in a vector of length at most 1.5 is approximately frac{1}{3}. Hence, the probability that the frog's final position is no more than 1.5 meters from its starting position after making 4 jumps of 1 meter each in random directions is frac{1{3}}. The final answer is boxed{textbf{(D)} dfrac{1}{3}}

question:an election, candidate Douglas won 60 percent of the total vote in counties X and Y. He won 72 percent of the vote in county X. If the ratio of people who voted in county X to county Y is 2:1, what percent of the vote did candidate Douglas win in county Y?

answer:Let's denote the total number of voters in county X as 2V and in county Y as V, according to the 2:1 ratio. Douglas won 72% of the vote in county X, so he won 0.72 * 2V votes in county X. We need to find the percentage of votes Douglas won in county Y. Let's denote this percentage as P. The total votes Douglas won in both counties is 60% of the total votes in both counties. The total number of votes in both counties is 2V + V = 3V. So, Douglas won 0.60 * 3V votes in total. The votes Douglas won in county Y can be calculated as the total votes he won minus the votes he won in county X: Votes in Y = Total votes won by Douglas - Votes won in X Votes in Y = (0.60 * 3V) - (0.72 * 2V) Now, let's calculate the votes in Y: Votes in Y = (1.80V) - (1.44V) Votes in Y = 0.36V Now we need to find the percentage of votes this represents in county Y. Since the total number of votes in county Y is V, the percentage P that Douglas won in county Y is: P = (Votes in Y / Total votes in Y) * 100% P = (0.36V / V) * 100% P = 0.36 * 100% P = 36% Therefore, candidate Douglas won boxed{36} percent of the vote in county Y.

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