answer:If each boat is 3 feet across and there must be a minimum of 2 feet between each boat or the riverbank, then the total width required for each boat and the gap between them is 3 + 2 = 5 feet. If the river is 42 feet across, then the maximum number of boats that can participate is 42 / 5 = 8.4 Since we cannot have a fraction of a boat, the maximum number of boats that can participate is 8. 8 The answer is: 8

answer:To find the points of intersection, we set the two equations equal to each other: 2x^2-4x+4=-x^2-2x+4. Simplifying, we get 3x^2-2x=0. Factoring out an x, we have x(3x-2)=0. So x=0 or x=frac{2}{3}. Substituting these values back into either of the original equations, we find that when x=0, y=4, and when x=frac{2}{3}, y=frac{20}{3}. Therefore, the points of intersection are (0,4) and left(frac{2}{3},frac{20}{3}right). The value of c-a is frac{2}{3}-0=boxed{frac{2}{3}}.The answer is: frac{2}{3}

answer:In base 7, the units digit is the remainder when the number is divided by 7. 52_7 and 62_7 both have units digit 2 in base 7. Adding the two numbers, we get 52_7 + 62_7 = 114_7. The units digit of 114_7 is boxed{4}. The answer is: 4

answer:To solve this problem, we need to determine the value of x, which represents the radius of the right circular cylinder. We know that the major axis of the ellipse is 50% longer than the minor axis. This means that the major axis is 1.5 times the length of the minor axis. The length of the major axis is given as 3. Let's set up the equation: Length of the major axis = 1.5 * Length of the minor axis 3 = 1.5 * Length of the minor axis To solve for the length of the minor axis, we divide both sides of the equation by 1.5: Length of the minor axis = 3 / 1.5 Length of the minor axis = 2 The radius of the right circular cylinder is equal to half the length of the minor axis of the ellipse. Therefore, the value of x is 2 / 2 = 1. The answer is: 1